How to exit from function in php
(PHP 4, PHP 5)
exit — Output a message and terminate the current script
Terminates execution of the script. Shutdown functions and object destructors will always be executed even if exit is called.
exit is a language construct and it can be called without parentheses if no
status is passed.
statusis a string, this function prints the
statusjust before exiting.
statusis an integer, that value will be used as the exit status and not printed. Exit statuses should be in the range 0 to 254, the exit status 255 is reserved by PHP and shall not be used. The status 0 is used to terminate the program successfully.
Note: PHP >= 4.2.0 does NOT print the
statusif it is an integer.
No value is returned.
Example #1 exit example
$filename = ‘/path/to/data-file’;
$file = fopen($filename, ‘r’)
or exit(“unable to open file ($filename)”);
Example #2 exit status example
//exit program normally
//exit with an error code
Example #3 Shutdown functions and destructors run regardless
public function __destruct()
echo 'Destruct: ' . __METHOD__ . '()' . PHP_EOL;
echo ‘Shutdown: ‘ . __FUNCTION__ . ‘()’ . PHP_EOL;
$foo = new Foo();
echo ‘This will not be output.’;
The above example will output:
Shutdown: shutdown() Destruct: Foo::__destruct()
Note: Because this is a language construct and not a function, it cannot be called using variable functions.
This language construct is equivalent to die().